Fazendo an = 1/k a(n+1) = (1/k)/(1+n.(1/k)) = 1/(k+n) k1=1 k2 = 1+1 k3 = 1+1+2 k4 = 1+1+2+3 k1993 = 1+1+2+3+...+1991+1992=1992.1993/2+1=996.1993+1 n1993=1/(996.1993+1) []s João
From: marconeborge...@hotmail.com To: obm-l@mat.puc-rio.br Subject: [obm-l] sequencia Date: Wed, 16 Feb 2011 12:45:44 +0000 Determinar a1993 para a sequencia definida por a0=1 e a(n+1)=an/(1+nan),para todo n natural.Desde ja agradeço.
