In message <[EMAIL PROTECTED]>,Jim Rees writes:
>I'm inclined to commit the new code and let Niklas or others work on making
>it better for large caches later. Comments?
how about choosing the sqrt(cachesize/1024) as the "average file size"?
cachesize avg file size(k) #files
150M ~12 12500
350M ~18 19444
1G ~32 32768
10G ~98 102040
20G ~143 146653
i choose sqrt() for no particular reason other than the numbers seems to
more closly match the original sizes for smaller caches and for larger
caches it matches the newly suggested average of 32k. for huge caches
it "safely" limits the amount of kernel space required.
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