On Wed, 29 Apr 2020 04:40:59 GMT, Ambarish Rapte <ara...@openjdk.org> wrote:
> Issue: > When tabs are permuted as mentioned in the issue description as, > 1. TabPane.getTabs().setAll(tab0, tab1) > 2. TabPane.getTabs().setAll(tab0, tab1, tab2, tab3); > the tab headers do not get permuted in same order as `TabPane.getTabs()`. > > => tab headers should be shown in order as tab0, tab1, tab2, tab3. > => but are show in order as tab2, tab3, tab0, tab1 > > Cause: > Newly added tabs(tab2, tab3) are not inserted at correct index. The index > `Change.getFrom()` (0) used from Change does > not remain valid after the tabs to be moved(tab0, tab1) are removed from > `tabsToAdd` list. > Fix: > Use the index of first newly added tab, from `TabPane.getTabs()`, which would > be always reliable. > > Verification: > No existing tests fail due to this change. > Added a system test which fails without and pass with fix. This pull request has now been integrated. Changeset: 6e039302 Author: Ambarish Rapte <ara...@openjdk.org> URL: https://git.openjdk.java.net/jfx/commit/6e039302 Stats: 71 lines in 2 files changed: 2 ins; 65 del; 4 mod 8237602: TabPane doesn't respect order of TabPane.getTabs() list Reviewed-by: kcr, fastegal ------------- PR: https://git.openjdk.java.net/jfx/pull/201
