Hi Girino. If you already have the owner's friend collection stored, you can use the opensocial.Collection getById method, passing in the ID of the current user. If the method returns null, the owner and viewer are not friends. This is the most straightforward technique at this point.
On a related note, you can use the opensocial.Person isOwner() method to determine whether the current user is also the owner. - Jason On Apr 17, 6:49 am, girino <[EMAIL PROTECTED]> wrote: > Hi, > > In my application I am trying to find out if the current person > viewing the application (VIEWER) is actually a friend of the OWNER or > just an unknown passer by. > > I am unable to find this in an easy way. Currently the only way I > found out is to recover all of VIEWER_FRIENDS and then iterate through > them checking if one of them is the owner. > > Is there an easier way to do this? > > Thanks, > Girino. --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Orkut Developer Forum" group. To post to this group, send email to opensocial-orkut@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/opensocial-orkut?hl=en -~----------~----~----~----~------~----~------~--~---
