Guys,
How do I call 'ls' from within a script without it also returning the
contents of the present working directory? Here is the line from my script:
ls -al /usr/lib/libGL.so*
Here is the output:
# ./linux/scripts/showLibConfig
250sata.pdf 7857.pdf Bannykh-ArizMedBoard.pdf Bannykh-TennMedBoard.pdf
bin broadway.pdf david.asc Desktop Documents linux log Pictures
public_html westlaw-renewal_20071129.pdf /usr/lib/libGL.so Config
lrwxrwxrwx 1 root root 10 2007-11-09 16:19 /usr/lib/libGL.so ->
libGL.so.1
lrwxrwxrwx 1 root root 12 2007-12-16 16:25 /usr/lib/libGL.so.1 ->
libGL.so.1.2
lrwxrwxrwx 1 root root 27 2007-12-16 16:25 /usr/lib/libGL.so.1.2 ->
/usr/X11R6/lib/libGL.so.1.2
-rwxr-xr-x 1 root root 391344 2007-09-21 20:34 /usr/lib/libGL.so.1.2.sav
as you can see, it looks like 'ls' is evaluated before 'ls -al
/usr/lib/libGL.so*' gets evaluated. How do I fix this?
--
David C. Rankin, J.D., P.E.
Rankin Law Firm, PLLC
510 Ochiltree Street
Nacogdoches, Texas 75961
Telephone: (936) 715-9333
Facsimile: (936) 715-9339
www.rankinlawfirm.com
--
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
