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The Sunday 2007-12-16 at 19:54 -0600, David C. Rankin wrote:
How do I call 'ls' from within a script without it also returning the
contents of the present working directory? Here is the line from my script:
ls -al /usr/lib/libGL.so*
Here is the output:
# ./linux/scripts/showLibConfig
250sata.pdf 7857.pdf Bannykh-ArizMedBoard.pdf Bannykh-TennMedBoard.pdf
bin broadway.pdf david.asc Desktop Documents linux log Pictures
public_html westlaw-renewal_20071129.pdf /usr/lib/libGL.so Config
lrwxrwxrwx 1 root root 10 2007-11-09 16:19 /usr/lib/libGL.so -> libGL.so.1
lrwxrwxrwx 1 root root 12 2007-12-16 16:25 /usr/lib/libGL.so.1 ->
libGL.so.1.2
lrwxrwxrwx 1 root root 27 2007-12-16 16:25 /usr/lib/libGL.so.1.2 ->
/usr/X11R6/lib/libGL.so.1.2
-rwxr-xr-x 1 root root 391344 2007-09-21 20:34 /usr/lib/libGL.so.1.2.sav
as you can see, it looks like 'ls' is evaluated before 'ls -al
/usr/lib/libGL.so*' gets evaluated. How do I fix this?
I can not reproduce your problem here. I wrote a script:
[EMAIL PROTECTED]:~> cat bin/pp
ls -al /usr/lib/libGL.so*
[EMAIL PROTECTED]:~> bin/pp
lrwxrwxrwx 1 root root 10 2007-11-03 03:01 /usr/lib/libGL.so -> libGL.so.1
lrwxrwxrwx 1 root root 12 2007-11-03 03:01 /usr/lib/libGL.so.1 ->
libGL.so.1.2
- -rwxr-xr-x 1 root root 567628 2007-02-18 02:59 /usr/lib/libGL.so.1.0.9631
- -rwxr-xr-x 1 root root 391344 2007-09-22 03:34 /usr/lib/libGL.so.1.2
So, you either have something else in your script that is interfering, or
there is a strangely named file(s) in that path.
Or an alias, as K.R. Foley sugests.
- --
Cheers,
Carlos E. R.
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