Good grief!

Here's me publishing war-n-peace to solve a problem that takes
4 lines of code...that's the last time I go out both nights at the weekend!!
;)

Please ignore my overly-engineered email when it finally arrives...

-----Original Message-----
Sent: 10 September 2001 16:10
To: Multiple recipients of list ORACLE-L


Hi,

    Try this query:

select customer,sales
from tablea x
where 3 > (select count(*) from tablea y where y.sales > x.sales)
order by x.sales desc;


Bill Carle
AT&T
Database Administrator
816-995-3922
[EMAIL PROTECTED]

 -----Original Message-----
Sent:   Monday, September 10, 2001 8:30 AM
To:     Multiple recipients of list ORACLE-L
Subject:        query for top customer

how to write a query to find top 3 customer
based on their sales .
eg.
TABLE A
customer       sales
A100          100
A101           200
A102           105
A103            109
A104            108

RESULTS should be..
A101       200
A103        109
A104        108

Thanks in advance
Brajesh        

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