Hello,
I was wondering if someone can help me with a report. I am stuck figuring out what I can do to complete it. Here is what I need to do:
for a given date range, i..e. start_date - end_date ('01/01/2003', '12/31/2003'), I need to count all "web", and "non-web" records. If seq_no > 4000, then it's web, otherwise non-web. seq_no is not unique. So it's like 2 different where claused in a single select. Could I somehow use CASE or decode to accomplish this. Here is what I am trying to do in select:
select id ,
to_char(received_date, 'YYYY-mm'),
id||yr||seq_no||ck MSNO
CASE WHEN seq_no > 4000 then count(seq_no) ELSE 0 end Count_WEB,
CASE WHEN seq_no <=4000 then count(seq_no) ELSE 0 END HARDCOPY
to_char(received_date, 'YYYY-mm'),
id||yr||seq_no||ck MSNO
CASE WHEN seq_no > 4000 then count(seq_no) ELSE 0 end Count_WEB,
CASE WHEN seq_no <=4000 then count(seq_no) ELSE 0 END HARDCOPY
from t
where received_date between '01/01/2003' and '12/31/2003'
group by id,
to_char(received_date, 'YYYY-mm'),
where received_date between '01/01/2003' and '12/31/2003'
group by id,
to_char(received_date, 'YYYY-mm'),
sequence_no,
id||yr||seq_no||ck
id||yr||seq_no||ck
/
AR 2003-01 AR030023T 0 1
AR 2003-01 AR0200302 0 1
AR 2003-01 AR020047K 0 1
AR 2003-01 AR020077N 0 1
AR 2003-01 AR0200302 0 1
AR 2003-01 AR020047K 0 1
AR 2003-01 AR020077N 0 1
I would like to show Year-Month once and count all instances of id||yr||seq_no||ck (primary_key) for that Year-Month, but not to break on it, and unfortunaley it won't let me do it without grouping on seq_no
Please advise!!!
Any help is greatly appreciated!
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