Hi Jethro, I'm a bit perplexed by your suggestion, as:
0.25 == 0.5 squared. Having the 0.5 multiplication within the brackets would force the operation to work on a temporary vec3 rather than a singe float so would take three times as much computation. Robert. On 4 February 2015 at 00:15, Jethro Leevers <j.leev...@aamgroup.com> wrote: > Hi, > > Looking in the osg\BoundingBox template it seems to have a function > radius2, this function seems to return 1/4 of the diameter squared, is > there a reason for this? > > Code: > > return 0.25*((_max-_min).length2()); > > > > I thought the following would be a more accurate radius2 function > > Code: > > return ((_max-_min)*0.5).length2(); > > > > > Thank you! > > Cheers, > Jethro[/code] > > ------------------ > Read this topic online here: > http://forum.openscenegraph.org/viewtopic.php?p=62584#62584 > > > > > > _______________________________________________ > osg-users mailing list > osg-users@lists.openscenegraph.org > http://lists.openscenegraph.org/listinfo.cgi/osg-users-openscenegraph.org >
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