Just right after I sent my mail, I realized that it's actually nonsense
(I had no time to answer earlier...) - so just forget about it :)

Regards
Carsten

BJ Hargrave  wrote
> What do you mean by "active" and how does that even related to ordering
> in a SortedSet (which was all my comment addressed)?
> -- 
> 
> *BJ Hargrave*
> Senior Technical Staff Member, IBM
> OSGi Fellow and CTO of the _OSGi Alliance_ <http://www.osgi.org/>_
> [email protected]_ <mailto:[email protected]>   
> 
> office: +1 386 848 1781
> mobile: +1 386 848 3788
> 
> 
> 
> 
> 
> 
> 
> From:        Carsten Ziegeler <[email protected]>
> To:        OSGi Developer Mail List <[email protected]>
> Date:        2011/01/15 05:25
> Subject:        Re: [osgi-dev] [DS] Improve reference support ?
> Sent by:        [email protected]
> 
> ------------------------------------------------------------------------
> 
> 
> 
> Yes, but in these cases all components implementing the service would be
> active though only one is used.
> 
> Regards
> Carsten
> 
> BJ Hargrave  wrote
>> Or SortedSet.first() :-)
>>
>> This is assuming you use a Collections.reverseOrder() comparator.
>> Otherwise the first element is the lowest ranking.
>> --
>>
>> *BJ Hargrave*
>> Senior Technical Staff Member, IBM
>> OSGi Fellow and CTO of the _OSGi Alliance_ <http://www.osgi.org/>_
>> [email protected]_ <mailto:[email protected]>                  
>>
>> office: +1 386 848 1781
>> mobile: +1 386 848 3788
>>
>>
>>
>>
>>
>>
>>
>> From:        Felix Meschberger <[email protected]>
>> To:        OSGi Developer Mail List <[email protected]>
>> Date:        2011/01/14 21:18
>> Subject:        Re: [osgi-dev] [DS] Improve reference support ?
>> Sent by:        [email protected]
>>
>> ------------------------------------------------------------------------
>>
>>
>>
>> Hi,
>>
>> Albeit a bit clumsy it is also possible using an internal Sorted
>> collection. The reference is converted to a multiple one and the
>> ServiceReferences are kept in, say, a SortedSet such that the service
>> with the highest ranking is always provided by
>> sortedSet.iterator().next().
>>
>> Regards
>> Felix
>>
>>
>> Am Freitag, den 14.01.2011, 11:34 +0100 schrieb Peter Kriens:
>>> Isn't this easily handed by a little helper class?
>>>
>>> Kind regards,
>>>
>>>                  Peter Kriens
>>>
>>> On 14 jan 2011, at 11:27, Carsten Ziegeler wrote:
>>>
>>> > Hi,
>>> >
>>> > we're using declarative services a lot - it's usually sufficient and
>>> > works pretty well :)
>>> >
>>> > The only drawback we're facing - and I've heard this from others as
> well
>>> > - is the lack of proper support for references and the service ranking
>>> > property: once a reference is bound it is not updated if a new
> component
>>> > providing the same service but with a higher service ranking arrives.
>>> > So, it gets more unpredictable and depends on the startup order of
>>> > services to what service such a reference is bound.
>>> > In these cases, you can't use DS.
>>> >
>>> > It would be great, to have a way to exactly define a reference that is
>>> > always bound to the service with the highest ranking. To be compatible
>>> > this has to be something new as we shouldn't change the current
>>> > behaviour. So maybe adding a new optional property to the reference tag
>>> > in the XML specifying if a rebound should happen due to service ranking
>>> > or something along these lines.
>>> >
>>> > WDYT?
>>> >
>>> > Regards
>>> > Carsten
>>> > --
>>> > Carsten Ziegeler
>>> > [email protected]
>>> > _______________________________________________
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> 
> 
> -- 
> Carsten Ziegeler
> [email protected]
> _______________________________________________
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> 
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-- 
Carsten Ziegeler
[email protected]
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