Product: Fedora
https://bugzilla.redhat.com/show_bug.cgi?id=905255

--- Comment #81 from Simone Caronni <negativ...@gmail.com> ---
The source code release contains all those licenses though. Ignoring the kernel
module files; this is the list of contained licenses:

> LGPL
> /var/lib/mock/fedora-18-x86_64/root/builddir/build/BUILD/open-vm-tools-9.2.2-
> 893683/tests/testVmblock/manual-blocker.c

> MIT/X11 (BSD like)
> /var/lib/mock/fedora-18-x86_64/root/builddir/build/BUILD/open-vm-tools-9.2.2-
> 893683/services/plugins/resolutionSet/vmwarectrlproto.h

> ISC
> /var/lib/mock/fedora-18-x86_64/root/builddir/build/BUILD/open-vm-tools-9.2.2-
> 893683/lib/misc/base64.c

> CDDL LGPL
> /var/lib/mock/fedora-18-x86_64/root/builddir/build/BUILD/open-vm-tools-9.2.2-
> 893683/lib/rpcOut/rpcout.c

> GPL (v2 or later)
> /var/lib/mock/fedora-18-x86_64/root/builddir/build/BUILD/open-vm-tools-9.2.2-
> 893683/config/ltmain.sh

Well, from what I see here:

https://fedoraproject.org/wiki/Licensing:FAQ#What_is_.22effective_license.22_and_do_I_need_to_know_that_for_the_License:_tag.3F

and here:

https://fedoraproject.org/wiki/Packaging:LicensingGuidelines#Multiple_Licensing_Scenarios

it seems you can only leave GPLv2 as the License. Quoting the Packaging
guidelines:

"The source code contains some .c files which are GPLv2+ and some other .c
files which are BSD. They're compiled together to form an executable. Since
some of the files are licensed as GPL, the resulting executable is also GPL.
The License tag should read: License: GPLv2+
Note that you do NOT need to list BSD in the License tag, the License tag
reflects the resulting, packaged, items in the binary RPM."

So, for my understanding your point seems valid and the License is valid as the
BSD/MIT files are compatible with the GPL.

I'm not a licensing expert, though. Anyone has anything to say regarding this?
Otherwise the package is good to go.

Thanks,
--Simone

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