I solved the issue: I only copied the python libs, but python needs two environment variables. When I start paraview with following environment variables it works: set PYTHONPATH=D:\Develop\Libraries90\DigPython\2.7.3.3\python-2.7.3\Lib set PYTHONHOME=D:\Develop\Libraries90\DigPython\2.7.3.3\python-2.7.3
uff, thanks for help best regards, happiest Gerald of the world.... -----Ursprüngliche Nachricht----- Von: Lodron, Gerald Gesendet: Donnerstag, 19. Dezember 2013 06:49 An: 'Utkarsh Ayachit' Cc: Paraview Developer (paraview-develop...@paraview.org); Paraview User (paraview@paraview.org) Betreff: WG: [Paraview-developers] Paraview with python problem Uh, now i am close in debugging: It closes in vtkPythonInterpreter::Initialize(); at vtkMatplotlibMathTextUtilities.cxx@115 I FOUND SOMETHING WITH PYTHON; YEAH Now I debugged further deeper: Inside bool vtkPythonInterpreter::Initialize(int initsigs /*=0*/) of vtkPythonInterpreter.cxx the Py_InitializeEx(initsigs); call closes my app, so there is something wrong with my python... I do not have python in debug mode compiled so I am stopping debugging here, but now I know where to look.... -----Ursprüngliche Nachricht----- Von: Lodron, Gerald Gesendet: Mittwoch, 18. Dezember 2013 23:03 An: 'Utkarsh Ayachit' Cc: Paraview Developer (paraview-develop...@paraview.org); Paraview User (paraview@paraview.org) Betreff: AW: [Paraview-developers] Paraview with python problem Hi again, so now i made a completely new empty build directory and i compiled it in 32 and 64 bit in release and debug mode (whereby I only had release libs of python) and all 4 variants close like before after applying any source...... So I can really say that there is no dll/lib mismatch.... Which python lib are you exactly using, I use one of my colleges which works for them. May there is something wrong inside them.... Best regards, Yours tired Gerald..... -----Ursprüngliche Nachricht----- Von: Utkarsh Ayachit [mailto:utkarsh.ayac...@kitware.com] Gesendet: Mittwoch, 18. Dezember 2013 17:08 An: Lodron, Gerald Cc: Paraview Developer (paraview-develop...@paraview.org); Paraview User (paraview@paraview.org) Betreff: Re: [Paraview-developers] Paraview with python problem Try a clean build :). I am sure that will resolve this issue (well, 90% sure). Nothing should close the application without exceptions or errors, unless the libraries are mismatched -- which could happen in case of a broken build. I'd strongly suggest doing a clean build. On Wed, Dec 18, 2013 at 10:55 AM, Lodron, Gerald <gerald.lod...@joanneum.at> wrote: > So, things seem to come to an end: > > (I selected the Sphere source and pressd Apply) > > vtkObjectBase *vtkCubeAxesRepresentationClientServerNewCommand() > { > return vtkCubeAxesRepresentation::New(); } > > Of vtkCubesAxesRepresentationClientServer @ 13 > > Where the New() seems to close my app. I then debugged to the > constructor of vtkCubeAxesRepresentation at > > this->CubeAxesActor = vtkCubeAxesActor::New(); on line 50 > > and then I came to the constructor of > vtkCubeAxesActor.cxx on line 131: > > this->XAxes[i] = vtkAxisActor::New(); > > > I must now go home and will restart the debugging tomorrow but any idea why > the standard New function of vtk could fail? > > Best regards, > Yours > Gerald > > > -----Ursprüngliche Nachricht----- > Von: Lodron, Gerald > Gesendet: Mittwoch, 18. Dezember 2013 16:21 > An: 'Utkarsh Ayachit' > Cc: 'Paraview Developer'; 'Paraview User' > Betreff: WG: [Paraview-developers] Paraview with python problem > > Ok forgot my last mail, it is not the vtkSMProxyManager, it is the > vtkSMSessionProxyManager where it jumps in and the name string of > name.toAscii().data(); is correct > > It closes in vtkSMSessionProxyManager:: RegisterProxy at > proxy->CreateVTKObjects();, I will debug forward.... > > -----Ursprüngliche Nachricht----- > Von: Lodron, Gerald > Gesendet: Mittwoch, 18. Dezember 2013 16:14 > An: 'Utkarsh Ayachit' > Cc: Paraview Developer (paraview-develop...@paraview.org); Paraview > User (paraview@paraview.org) > Betreff: AW: [Paraview-developers] Paraview with python problem > > > It closes in > > pxm->RegisterProxy("representations", pcTest, reprProxy); > > at pqObjectBuilder.cxx at line 527, and when I set a breakpoint into > registerProxy of vtkSMProxyManager it gets never hit. It seems that > the name.toAscii().data() is corrupted, but name is a vaild string > "DataRepresentation1". When I write > > const char* pcTest = name.toAscii().data(); > //pxm->RegisterProxy("representations", name.toAscii().data(), reprProxy); > pxm->RegisterProxy("representations", pcTest, reprProxy); > > and watch at pcTest it is " > îþîþîþîþîþîþîþîþîþîþîþîþîþîþîþîþîþîþîþîþîþîþîþîþîþîþîþîþîþîþîþîþîþîþîþ > îþîþîþîþîþîþîþîþîþîþîþîþîþîþîþîþîþîþîþîþîþîþîþîþîþîþîþîþîþîþîþîþîþîþîþ > îþîþîþîþîþîþîþîþîþîþÓ6 > > ¡~ hêè Xlø " so it seems that: > > Name.toAscii().data() is not allowed in that combination OR The memory is > completely corrupted from somewhere else...... > > > > > > > -----Ursprüngliche Nachricht----- > Von: Utkarsh Ayachit [mailto:utkarsh.ayac...@kitware.com] > Gesendet: Mittwoch, 18. Dezember 2013 15:52 > An: Lodron, Gerald > Cc: Paraview Developer (paraview-develop...@paraview.org); Paraview > User (paraview@paraview.org) > Betreff: Re: [Paraview-developers] Paraview with python problem > > Weird. Let's try this, but a break point in that method. It'll only be called > once after you hit "apply". Then step into the code, including > createDataRepresentation(..). If you cannot step, I think it's a problem with > mismatched/improperly built libraries or something. If the call stack starts > making no sense, it's definitely that, and I'd recommend a clean build -- > start with an empty binary directory. > > Utkarsh > > On Wed, Dec 18, 2013 at 9:45 AM, Lodron, Gerald <gerald.lod...@joanneum.at> > wrote: >> Hi, >> >> I am currently debugging, it closes (not crashing!) in >> >> pqDataRepresentation* pqDisplayPolicy::newRepresentation(pqOutputPort* port, >> pqView* view) const >> { >> return pqApplicationCore::instance()->getObjectBuilder()-> >> createDataRepresentation(port, view); } Of pqDisplayPolicy.cxx >> >> Here i cannot debug in for any reason (i come somewhere into assembler of qt >> and when I step out it closes). I will try debugging more ... >> PS: I also checked the successful RequestData return of the sources so the >> source is correctly applied, it closes afterwards... >> >> Gerald >> >> >> -----Ursprüngliche Nachricht----- >> Von: Utkarsh Ayachit [mailto:utkarsh.ayac...@kitware.com] >> Gesendet: Mittwoch, 18. Dezember 2013 15:40 >> An: Lodron, Gerald >> Cc: Paraview User (paraview@paraview.org); Paraview Developer >> (paraview-develop...@paraview.org) >> Betreff: Re: [Paraview-developers] Paraview with python problem >> >> Gerald, >> >> Since you compiled from source, can you do debug build and then run through >> a debugger to see why it's aborting? I don't think I've seen this behaviour >> before. I wonder if its related to the dependency issue. Was this a clean >> build or were you doing an incremental build? >> >> Utkarsh >> >> On Wed, Dec 18, 2013 at 9:19 AM, Lodron, Gerald <gerald.lod...@joanneum.at> >> wrote: >>> Hi >>> >>> >>> >>> I successfully compiled paraview 4.1.0 with python 2.7.3 enabled in 32 bit. >>> Paraview also starts but when I generate ANY data (over open file or >>> over >>> sources->Sphere or box or anything else etc.) it closes after >>> sources->pressing >>> Apply. Does anyone has a clue what could cause that strange behaviour? >>> >>> >>> >>> Thanks for advice... >>> >>> >>> >>> Best regards >>> >>> Gerald Lodron >>> >>> >>> >>> _________________________________________________________________ >>> >>> >>> >>> JOANNEUM RESEARCH Forschungsgesellschaft mbH >>> >>> >>> >>> DIGITAL - Institute for Information and Communication Technologies >>> >>> Steyrergasse 17, 8010 Graz, Austria >>> >>> >>> >>> phone: +43 316 876-1751 >>> >>> fax: +43 316 8769-1751 >>> >>> e-mail: gerald.lod...@joanneum.at >>> >>> web: www.joanneum.at/digital >>> >>> _________________________________________________________________ >>> >>> >>> >>> This message and any attached files are confidential and intended >>> solely for the addressee(s). Any publication, transmission or other >>> use of the information by a person or entity other than the intended >>> addressee(s) is prohibited. If you receive this in error please >>> contact the sender and delete the material. 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