In my happy world, one could perform the following: [coords 0 -1 1 1 80 90 1 100 100;( | | [s $!]
With the example above, one could perform canvas operations on the current canvas, ie: "this". So to answer your question, $! would be the equivalent to whatever name you supplied in [namecanvas], so it's type would be that of the canvas, an object type. Therefore, if you attempted the following, no error should occur (again, in my happy world) [clear( | | [s $1] Miller? Cheers, ~Brandon On Thu, Sep 30, 2010 at 1:22 PM, Mathieu Bouchard <ma...@artengine.ca>wrote: > On Thu, 30 Sep 2010, brandon zeeb wrote: > > If Miller wants to remove [namecanvas], just give us a "this" expression! >> What about $! ? >> > > What would be the type of $! ? > > I don't think that there is any atom-type for supporting the feature that > you suggest. > > see also http://lists.puredata.info/pipermail/pd-list/2006-02/035454.html > > > _______________________________________________________________________ > | Mathieu Bouchard ------------------------------ Villeray, Montréal, QC >
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