Le 2011-10-11 à 12:42:00, Lorenzo Sutton a écrit :
No, no. I propose that with expr, expr~ and fexpr~ you count one object for each operator you use so: [expr~ sin($v1 + 1) * sqrt ($v1)]would be 4 objects :-)
[lop~] is essentially made from one [rpole~], one [*], one [/], one [samplerate~] and one [loadbang], so why wouldn't you count it as five ?
etcætera... how do you count [biquad~] ? how do you count a [table] ? ______________________________________________________________________ | Mathieu BOUCHARD ----- téléphone : +1.514.383.3801 ----- Montréal, QC
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