On 11/10/2011 17:02, Mathieu Bouchard wrote:
Le 2011-10-11 à 12:42:00, Lorenzo Sutton a écrit :
No, no. I propose that with expr, expr~ and fexpr~ you count one
object for each operator you use so: [expr~ sin($v1 + 1) * sqrt ($v1)]
would be 4 objects :-)
[lop~] is essentially made from one [rpole~], one [*], one [/], one
[samplerate~] and one [loadbang], so why wouldn't you count it as five ?
etcætera... how do you count [biquad~] ?
how do you count a [table] ?
Hey, hey.. I was joking :P
Still 16 objects, but then.. you can put it on when you get those oh so
bothersome marketing calls.
Lorenzo
#N canvas 217 182 450 437 10;
#X obj 44 303 dac~;
#X obj 85 171 list split;
#X obj 86 220 unpack f f;
#X obj 85 104 t b f;
#X obj 86 195 list split 2;
#X obj 84 43 random 8;
#X obj 244 -15 tgl 25 0 empty empty empty 17 7 0 10 -262144 -1 -1 1
1;
#X obj 86 263 bp~ 1400 20;
#X text 123 -73 1 START METRO;
#X text 123 -53 2 START DSP;
#X msg 85 127 1000 1400 700 1150 700 1800 500 2300 320 2500 600 1050
500 900 320 800;
#X obj 13 -39 osc~ 40;
#X obj 171 22 metro 960;
#X obj 13 263 bp~ 1000 10;
#X obj 84 21 metro 180;
#X obj 15 -16 expr~ 15 * (pow(pow($v1 \, 2) \, 300));
#X obj 84 68 expr $f1 *2 \; $f2 * 0.01 + 30;
#X obj 171 44 random 1800;
#X connect 1 1 4 0;
#X connect 2 0 13 1;
#X connect 2 1 7 1;
#X connect 3 0 10 0;
#X connect 3 1 1 1;
#X connect 4 0 2 0;
#X connect 5 0 16 0;
#X connect 6 0 12 0;
#X connect 6 0 14 0;
#X connect 7 0 0 0;
#X connect 7 0 0 1;
#X connect 10 0 1 0;
#X connect 11 0 15 0;
#X connect 12 0 17 0;
#X connect 13 0 0 0;
#X connect 13 0 0 1;
#X connect 14 0 5 0;
#X connect 15 0 7 0;
#X connect 15 0 13 0;
#X connect 16 0 3 0;
#X connect 16 1 11 0;
#X connect 17 0 16 1;
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