On 06/12/12 15:31, Hans-Christoph Steiner wrote:
Leaving out [rate~] should use less CPU since [rate~] doesn't have to
do the analysis part, if I understand it correctly.
If I understand correctly what rate~ does, the argument is actually a
factor, so I thnk the frequency for the phasor~ has to be 1 / factor...
So for example
[rate~ 1.5]
is [phasor~ 0.666667]
Lorenzo.
.hc
On Dec 6, 2012, at 9:24 AM, Alexandros Drymonitis wrote:
Don't think I really follow. Each [rate~] actually outputs a
[phasor~] with a different frequency (different frequency ratio), all
driven by the same [phasor~]. How can you send a value from one
number box to all [phasor~]s?
On Thu, Dec 6, 2012 at 4:18 PM, Hans-Christoph Steiner <h...@at.or.at
<mailto:h...@at.or.at>> wrote:
Why not just use a phasor~ per rate~ and then have the frequency
of all them controlled by the same number box?
.hc
On Dec 6, 2012, at 8:57 AM, Alexandros Drymonitis wrote:
copy this patch
http://www.youtube.com/watch?v=6P4Ezz9aWa8&feature=plcp
On Thu, Dec 6, 2012 at 3:55 PM, Simon Iten <itensi...@gmail.com
<mailto:itensi...@gmail.com>> wrote:
What are you trying to accomplish?
On Dec 6, 2012 2:48 PM, "Alexandros Drymonitis"
<adr...@gmail.com <mailto:adr...@gmail.com>> wrote:
How can one implement Max's [rate~] in Pd? [rate~] takes
a signal from a [phasor~] and according to its argument
it scales the frequency (roughly speaking). So
[phasor~ 1]
|
[rate~ 1.5]
will actually give a [phasor~ 1.5]. I thought of [wrap]
but that won't do the trick with non-integers.
Any ideas?
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