On Sun, Jul 17, 2005 at 11:38:05AM +0900, SADAHIRO Tomoyuki wrote: > Hello, > > \c\ is an only case (afaik) of escape sequence ending with backslash. > Though perlop explains how to find the end of quoted constructs > in detail, it may be a trap. > > Regards, > SADAHIRO Tomoyuki > > diff -ur perl~/pod/perlop.pod perl/pod/perlop.pod > --- perl~/pod/perlop.pod Fri Jul 15 18:33:32 2005 > +++ perl/pod/perlop.pod Sun Jul 17 10:50:41 2005 > @@ -1668,6 +1668,11 @@ > the example above is not C<m//x>, but rather C<m//> with no C</x> > modifier. So the embedded C<#> is interpreted as a literal C<#>. > > +Also no attention is paid to C<\c\> during this search. > +Thus the second C<\> in C<qq/\c\/> is interpleted as a part of C<\/>, > +and the following C</> is not recognized as delimiter. > +Instead, use C<\034> or C<\x1c> at the end of quoted constructs. > + > =item Removal of backslashes before delimiters > > During the second pass, text between the starting and ending > END OF PATCH
I've long considered this a bug. I'd rather not document it, or document it explicitly as a bug. IMO "finding the end" is inconsistent with later processing, and \c\ should be treated as a complete character.
