David Corbin wrote:
> 
> Ariel Scolnicov wrote:
> >
> >
> > So how do I make C<foo> into an array in the first place?  Well, I say
> > something like C<foo = (1,2,3)>.  But wait -- that's ambiguous!  Is
> > C<foo> now a copy of the list (1,2,3) (in which case it's an array),
> > or is it a reference to (1,2,3) (in which case it's a scalar)?  In the
> > first case, C<foo = bar> (where C<bar> is an array, assuming I could
> > ever assign an array to a variable) would perform a copy, while in the
> > second it would make the two variables refer to the same thing.
> 
> Actually, if you wanted an array, you'd say C<foo = [1,2,3]>.  Very
> unambiguous.



ARG! I mean to say if you wanted an array REFERENCE, not an array. 
Sorry for the confusion.

> 
> >
> > --
> > Ariel Scolnicov        |"GCAAGAATTGAACTGTAG"            | [EMAIL PROTECTED]
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> 
> --
> David Corbin
> Mach Turtle Technologies, Inc.
> http://www.machturtle.com
> [EMAIL PROTECTED]

-- 
David Corbin            
Mach Turtle Technologies, Inc.
http://www.machturtle.com
[EMAIL PROTECTED]

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