On Mon, 23 Apr 2001 13:19:24 +0100, Graham Barr <[EMAIL PROTECTED]> wrote:
> > $a = $b ~ $c; # Mmm!
> >
> > I like that last one a lot, because it doesn't disturb anything.
> > You'd have to alter ~'s precedence so that binary ~ is higher
> > than named unary operators. (It's print($a~$b), not print $a (~b).)
>
> I am not sure I do like the use of ~ here. It does not screan concatenate
> to me (but then again neither did . when I started perl)
>
> I am thinking that maybe it should be a 2 character operator with at
> least one of then being + as + is common in many other languages
> for doing concatenation.
like ++ ?
we have ** already for exponents
--
H.Merijn Brand Amsterdam Perl Mongers (http://www.amsterdam.pm.org/)
using perl-5.6.1, 5.7.1 & 623 on HP-UX 10.20 & 11.00, AIX 4.2, AIX 4.3,
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ftp://ftp.funet.fi/pub/languages/perl/CPAN/authors/id/H/HM/HMBRAND/
