Thanks, Timo and Moritz. > Because say() is a high-level function that uses the lower-level > $*OUT.print under the hood.
Ah, so an alternative would be to just redefine the sub:
my $str = '';
sub say($arg) {
$str ~= $arg
}
say 'hi';
use Test;
is $str, 'hi', 'works';
Works great!
Brian
