I imagine P6 may one day be changed to do as you suggest.
But for now I think something like this is the closest you'll get:
subset Str_Int of List where Str, Int;
sub foo (--> Str_Int) { return 'a', 42 }
--
raiph
On Fri, Oct 12, 2018 at 11:23 PM ToddAndMargo via perl6-users <
perl6-us...@perl.org> wrote:
> On 10/12/18 2:35 PM, Curt Tilmes wrote:
> >
> >
> > On Fri, Oct 12, 2018 at 5:08 PM ToddAndMargo via perl6-users
> > <perl6-us...@perl.org <mailto:perl6-us...@perl.org>> wrote:
> >
> > >> On 10/12/18 12:52 PM, Curt Tilmes wrote:
> > >> > You could make a subset for the List your're trying to
> > return:
> > >> >
> > >> > subset liststrint of List where .[0] ~~ Str && .[1] ~~
> Int;
> > >> > sub RtnOrd( Str $Char --> liststrint) ...
> > >>
> > >> I am confused.
> > >>
> > >> I want to get the --> syntax correct for `return $Char,
> > ord($Char)`
> >
> > On 10/12/18 1:49 PM, Brad Gilbert wrote:
> > > That would be `List`
> > >
> > > sub RtnOrd( Str $Char --> List ){ $Char, ord($Char) }
> > > say RtnOrd "A"
> > > # (A 65)
> >
> > $ p6 'sub RtnOrd( Str $Char --> List ){return $Char, ord($Char)}; say
> > RtnOrd "A";'
> > (A 65)
> >
> > But "List" does not tell my what is in the list.
> >
> >
> > You can create a brand new type, a subset of Lists where the first
> element
> > (we refer to with [0]) is of type Str (~~ Str) and the second element of
> > the List
> > (we refer to with [1]) is of type Int (~~ Int).
> >
> > Define it like this:
> > subset list-str-int of List where .[0] ~~ Str && .[1] ~~ Int;
> >
> > then you can say that your routine returns a list that looks like that:
> >
> > sub RtnOrd( Str $Char --> list-str-int)
> >
>
> Is there any way to say I am return two things: a string and an integer?
>
