On Fri, Oct 12, 2018 at 3:14 PM ToddAndMargo via perl6-users
<perl6-us...@perl.org <mailto:perl6-us...@perl.org>> wrote:
>> On Fri, Oct 12, 2018 at 3:32 PM ToddAndMargo via perl6-users
>> <perl6-us...@perl.org <mailto:perl6-us...@perl.org>
<mailto:perl6-us...@perl.org <mailto:perl6-us...@perl.org>>> wrote:
>>
>>
>> But this does not?
>>
>> $ p6 'sub RtnOrd( Str $Char --> Str, Int ){return $Char,
>> ord($Char)}; say RtnOrd "A";'
>>
>> ===SORRY!=== Error while compiling -e
>> Malformed return value (return constraints only
allowed at the
>> end
>> of the signature)
>> at -e:1
>> ------> sub RtnOrd( Str $Char --> Str⏏, Int ){return
$Char,
>> ord($Char)}; say R
On 10/12/18 12:52 PM, Curt Tilmes wrote:
> You could make a subset for the List your're trying to return:
>
> subset liststrint of List where .[0] ~~ Str && .[1] ~~ Int;
> sub RtnOrd( Str $Char --> liststrint) ...
I am confused.
I want to get the --> syntax correct for `return $Char, ord($Char)`
On 10/12/18 1:49 PM, Brad Gilbert wrote:
That would be `List`
sub RtnOrd( Str $Char --> List ){ $Char, ord($Char) }
say RtnOrd "A"
# (A 65)
$ p6 'sub RtnOrd( Str $Char --> List ){return $Char, ord($Char)}; say
RtnOrd "A";'
(A 65)
But "List" does not tell my what is in the list.
