Re: buf to integer?

[ToddAndMargo via perl6-users]

On 2/8/19 2:59 AM, The Sidhekin wrote:

  The "elegant" way I'd do it, is using unpack(): https://docs.perl6.org/routine/unpack

  It's experimental, so a declaration is needed, but Buf does Blob, so otherwise, it's straight to the point:

$ perl6 -e 'use experimental :pack; my Buf $x=Buf.new(0xAE,0x5D,0x5C,0x72); say $x.unpack("L").base(0x10);'

725C5DAE
$


Eirik

Thank you!