On 2/8/19 1:37 PM, Kevin Pye wrote:
Unpack is very useful if you have multiple items you want to unpack, and
if you're familiar with the Perl 5 unpack then there's the P5pack module
(which isn't a full implementation of Perl 5's unpack, but is useful for
simpler things). If you want to unpack something from the middle of a
Buf or Blob then you'll need to explicitly skip over the beginning of
the buffer using "x", whereas read-int32 has an explicit position argument.
On Fri, 8 Feb 2019 at 22:00, The Sidhekin <sidhe...@gmail.com
<mailto:sidhe...@gmail.com>> wrote:
On Fri, Feb 8, 2019 at 7:36 AM Todd Chester via perl6-users
<perl6-us...@perl.org <mailto:perl6-us...@perl.org>> wrote:
I am dealing with a Buf what includes 32 bit integers, but
they are entered somewhat backwards as view with hexedit:
AE 5D 5C 72 represents the number 725C5DAE
This is what I have come up with to convert this type of
number in a buffer to and integer
$ p6 'my Buf $x=Buf.new(0xAE,0x5D,0x5C,0x72); my int32 $i=$x[3]
+< 0x18
+ $x[2] +< 0x10 + $x[1] +< 0x08 + $x[0]; say $x; say
$i.base(0x10);'
Buf:0x<ae 5d 5c 72>
725C5DAE
Is there a more "elegant" way to do this?
The "elegant" way I'd do it, is using unpack():
https://docs.perl6.org/routine/unpack
It's experimental, so a declaration is needed, but Buf does Blob,
so otherwise, it's straight to the point:
$ perl6 -e 'use experimental :pack; my Buf
$x=Buf.new(0xAE,0x5D,0x5C,0x72); say $x.unpack("L").base(0x10);'
725C5DAE
$
Eirik
Interesting. Thank you!
