David L. Nicol wrote:
>
>Are there really situations where
>
> $$reference = An Expression;
>
>is clearer than
>
> $reference = \(An Expression);
>
>?
Eric is confused. I don't know about in Perl 6-to-be, but in Perl 5
those two mean totally different things:
$foo = \$bar; # sets $foo to be a ref to $bar
$$foo = "hi mom"; # sets $bar to "hi mom"
$foo = \"hi mom"; # sets $foo to be a ref to "hi mom"
----------------------------------------------------------------------
Eric J. Roode [EMAIL PROTECTED]
Senior Software Engineer, Myxa Corporation
