On Monday 10 September 2001 09:00 pm, Dan Sugalski wrote: > >But how does the interpreter know where a lexical scope begins > >and ends in the bytecode? For example, a "jump FOO" might change > >scopes. How is the scope discovered? > > jump FOO > > doesn't change scope. Is that a "doesn't" or "won't"? -- Bryan C. Warnock [EMAIL PROTECTED]
- PDD 6: Parrot Assembly Language Dan Sugalski
- Re: PDD 6: Parrot Assembly Language Matthew Cline
- Re: PDD 6: Parrot Assembly Language Bryan C . Warnock
- Re: PDD 6: Parrot Assembly Language Simon Cozens
- Re: PDD 6: Parrot Assembly Language Dan Sugalski
- Re: PDD 6: Parrot Assembly Language Ken Fox
- Re: PDD 6: Parrot Assembly Language Dan Sugalski
- Re: PDD 6: Parrot Assembly Language Ken Fox
- Re: PDD 6: Parrot Assembly Language Dan Sugalski
- Re: PDD 6: Parrot Assembly Language Bryan C . Warnock
- Re: PDD 6: Parrot Assembly Language Ken Fox
- Re: PDD 6: Parrot Assembly Language Dan Sugalski
- Re: PDD 6: Parrot Assembly Language Dan Sugalski
- Re: PDD 6: Parrot Assembly Language Bryan C . Warnock
- Re: PDD 6: Parrot Assembly Language Ken Fox
- Re: PDD 6: Parrot Assembly Language Dan Sugalski
- Re: PDD 6: Parrot Assembly Language Bryan C . Warnock