Dan Sugalski <[EMAIL PROTECTED]> wrote: > #2 is what you get with normal assignment. $foo = $bar, for example. > $foo's assign vtable method is called with $bar as a parameter. $foo > figures out what it should do--if it's a tied variable of some sort > it should perform its assign action. (This includes throwing an > exception if the assignment isn't valid) Otherwise it should > typecheck the RHS and morph itself into the RHS's type.
So in the following: my Complex $c = 3+4i; my $plain = 1.1; $plain = $c; I presume that $plain ends up as type Complex (with value 3+4i)? If so, how does $plain know how to "morph itself into the RHS's type"?
