When junctions collapse, is that reflected back in the original junction, as it should be (QM-wise)?
$foo = 1 | 2 | 4 print $foo; # Foo is now just one of (1, 2, 4); i.e. not a junction If so, what is perl going to do about the computationally expensive entanglement thingy? $x = 0 | 1; $y = 0 | 1; $z = $x * $y; print $z; # 0 with 0.75 probability and 1 with 0.25 # If 0 was printed, then $x | $y == 0 # If 1 was printed, then $x & $y == 1 Here, are $x and $y collapsed yet, or are they still in an entangled superposition? Luke