On Thu, Dec 12, 2002 at 10:40:20PM -0000, Smylers wrote:
> What if the thing being C<sort>ed (or whatever) is not an array but a
> list?
>
> @out = sort $scalar, @array, result_of_calling_function($param);
>
> Would the list have to be stored in an array before it could be sorted?
I would hope Perl would be smart enough to allow this:
@out = ($scalar, @array, result_of_calling_function($param)).sort
which Ruby does:
$ ruby -wle 'out = ["foo", "bar"].sort; print out.join " "'
bar foo
but as I said, I find the Lisp flow style worth keeping.
@out = join "\n", map {...} grep {...} sort {...} @foo
--
Michael G. Schwern <[EMAIL PROTECTED]> http://www.pobox.com/~schwern/
Perl Quality Assurance <[EMAIL PROTECTED]> Kwalitee Is Job One
Pancakes is the better part of valor.
http://www.goats.com/archive/971202.html
