Ingo Blechschmidt <[EMAIL PROTECTED]> writes:
> Hi,
>
> sub foo (Code $code) {
> my $return_to_caller = -> $ret { return $ret };
>
> $code($return_to_caller);
> return 23;
> }
>
> sub bar (Code $return) { $return(42) }
>
> say foo &bar; # 42 or 23?
>
> I think it should output 42, as the return() in the pointy
> block $return_to_caller affects &foo, not the pointy block.
> To leave a pointy block, one would have to use leave(), right?
That's how it's defined in the relevant Apocalypse. And that's how I hope it'll
stay.
