[perl #77616] ~ operator in regexp reverts capture order, but it should not

[Will Coleda via RT]

On Thu Aug 25 03:17:17 2011, bbkr wrote:
> [12:14] <bbkr_> nom: say so "abc" ~~ /a ~ (c) (b)/; say $0 # this is
> weird. in rakudo it captured incorectly ( #77616 ) in nom it does not
> capture at all.
> [12:14] <p6eval> nom b0da69: OUTPUT«Bool::True␤Any()␤»

Current nom behavior:

> say so "abc" ~~ /a ~ (c) (b)/; say $0
True
｢b｣

-- 
Will "Coke" Coleda