Damian Conway <[EMAIL PROTECTED]> writes:
>
> > And package::subroutine should go the way of package`subroutine
> as
>
> > package.subroutine will work and become the preferred method :),
> no?
>
>
> Err...no. They're still not the same thing in Perl 6:
>
> package::subroutine(@args) --> package::subroutine(@args)
> package.subroutine(@args) --> package::subroutine('package',@args)
>
>
> And you'll still need the package separator version to take the
> address of the subroutine.
Please tell me there will be a way to work out if you're called as a
subroutine or as a method.
