> Please tell me there will be a way to work out if you're called as a
> subroutine or as a method.
Yes. Subroutines and methods will inhabit different namespaces
(modules and classes respectively):
module X;
sub s { print "I am the very model of a modern Perl 6 subroutine\n" }
class X {
method s { print "I'm trying to be objective here\n" }
}
X::s(); # I am the very model...
X.s(); # I'm trying to be...
Though I'm by no means certain that Larry will allow both a module X and a
class X at the same time.
Damian
