* Damian Conway ([EMAIL PROTECTED]) [08 Jul 2002 10:27]: [...] > > given my Doberman $sis is female = .dog[0] but pregnant -> $mother { > > for my Doberman @puppies = new Doberman x $mother.littersize
> I'd have thought you'd need: > for my Doberman @puppies = (new Doberman) x $mother.littersize Is it just my reading or would that return the same Doberman as each puppy? i.e. Doberman.new is only called once and then duplicated? cheers, -- Iain 'Spoon' Truskett. <http://eh.org/~koschei/>