On Wed, 30 Oct 2002, John Williams wrote:
: They are different in the "scalar [op] list" case, as explained here:
: <http://archive.develooper.com/perl6-language%40perl.org/msg10961.html>
:
: ($a = 0) [+=] @b; # sum
: ($a = 1) [*=] @b; # product
: ($a ='') [~=] @b; # cat
That's almost a reduce. Pity you have to include a variable.
But since rvalues are illegal on the left side of an assignment, we
*could* go as far as to say that
0 [+=] @b; # sum
1 [*=] @b; # product
'' [~=] @b; # cat
dwim into reduce operators rather than being illegal.
Larry
