Re: is static? -- Question

[arcadi shehter]

Matthijs van Duin writes:
 > 
 > >does it mean that this is legitimate 
 > >
 > >  sub a {
 > >      state $x;
 > >      my $y;
 > >      state sub b { state $z ; return $x++ + $y++ + $z++ ; }
 > >      return &b;   # is a \ before &b needed?
 > >  }
 > 
 > No, since you can't refer to $y in that sub (perl 5 actually allows you to 
 > do that but gives a warning 'Variable "%s" will not stay shared' - but I 
 > hope perl 6 will simply give a compile-time error)

so, the only problem here is that the closure of "sub b" will be
evaluated only once and the following exemple  will work ? 

 sub a {
     state $x;
     state sub b { ... } ;
     my $y;
     &b = sub { state $z ; return $x++ + $y++ + $z++ ; }
     return &b;   # is a \ before &b needed?
 }

also , is that correct ?  

sub new_counter($start=0) { 
    return sub { 
                 state $cnt =  $start; 
                 return ++$cnt;
               }         
}

our &counter = new_counter ;
our &another_counter = new_counter ;

print counter, counter, another_counter, another_counter ;

#prints: 1, 2, 3, 4 


thanks, 
arcadi