On Tue, 2004-09-14 at 06:45, Michele Dondi wrote:
[... snip ...]
> Now I want to take a list of templates, say $t1, ... $tn and get the 
> result of
> 
>   $result = pack $tn, ... pack $t2, pack $t1, @input;

Assuming Perl 6 has a "pack", which it may not:

        for @t {
                $result = pack $_, ($result // @input);
        }

no?

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