Jon Lang suggested: > Start with the addition operator, '1 + 1'. Apply the reducing > metaoperator to it so that it works syntactically like a function: > '[+] 1, 1'. Instead of calling it, pass a code reference to it: > '&[+]'.
No. &[+] isn't the Code object for [+]; it's the Code object for &infix:<+>. See http://perlcabal.org/syn/S03.html#Nesting_of_metaoperators > What I'm wondering is how the list knows to feed two items into '[+]'. > While 'infix:<+>' must accept exactly two arguments, '[+]' can accept > an arbitrarily long (or short) list of arguments. And since &[+] is &infix:<+>, that's how it knows. :-) Damian
