I wrote: > ISTM that getting rid of the division obviates the concern that the > nentries condition is too expensive,
Also, we could make it slightly cheaper yet, by changing the condition to hctl->freeList[0].nentries > (long) (hctl->max_bucket) ie drop the +1. I'd argue that this is actually a more faithful rendition of the previous condition, since what we had before was basically hctl->freeList[0].nentries >= (long) (hctl->max_bucket + 1) regards, tom lane