Tom Lane wrote:
Dennis Haney <[EMAIL PROTECTED]> writes:
Consider this example:
SELECT * FROM a,b WHERE a.id = b.id AND (a.id) IN (SELECT c.id FROM c)
the possible execution trees are {{a,b}, {c}}, {{a,c},{b}} and the code
seems to also permit {{b,c},{a}}.
No, it does not --- as you say, that would give wrong answers. That
case is eliminated by the tests following this comment:
* JOIN_IN technique will work if outerrel includes LHS and
* innerrel is exactly RHS; conversely JOIN_REVERSE_IN handles
* RHS/LHS.
*
* JOIN_UNIQUE_OUTER will work if outerrel is exactly RHS;
* conversely JOIN_UNIQUE_INNER will work if innerrel is
* exactly RHS.
Joining {b,c} to {a} does not meet any of those four allowed cases.
Exactly my point... So why ever bother creating the {b,c} node which is
legal by the above definition?
--
Dennis
use Inline C => q{void p(char*g){
printf("Just Another %s Hacker\n",g);}};p("Perl");
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