Hannu Krosing <[EMAIL PROTECTED]> writes:
> On K, 2005-07-13 at 16:08 +0800, Christopher Kings-Lynne wrote:
>> Does it know that the input to the sort routine is already sorted and
>> hence is a no-op?
> Yes
No, but in most cases this will use an index and hence will assume that
the index is responsible for ordering.
regards, tom lane
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