Phuong Ma <[EMAIL PROTECTED]> writes:
> I'm using PostgreSQL version 7.1, and I'm having trouble with the LIKE
> statement. How would I find the value "a\bc"? I tried using the
> backslash to escape it: LIKE 'a\\b%';
I think you need four backslashes. The string-literal parser eats one
level of backslashes, but you need the pattern that arrives at LIKE
to look like "a\\b%".
BTW, "PostgreSQL version 7.1" does not exist yet.
regards, tom lane
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