I'm using PostgreSQL version 7.1, and I'm having trouble with the LIKE statement. How would I find the value "a\bc"? I tried using the backslash to escape it: LIKE 'a\\b%'; If I specify: LIKE 'a\\bc', then it works, but if I wanted it to look for consecetive characters after the c, using the %, then it returns other values besides what I'm looking for. I also have the same problem with percent (%). I have a test string with the value "ab%c", and I want to look for that using LIKE. I tried: LIKE 'ab\%c', LIKE 'ab%%', and LIKE 'ab\%_', but these statements not only returned what I was looking for, but also other values: "abc","ABC", and "Abc". Phuong ---------------------------(end of broadcast)--------------------------- TIP 3: if posting/reading through Usenet, please send an appropriate subscribe-nomail command to [EMAIL PROTECTED] so that your message can get through to the mailing list cleanly
