[EMAIL PROTECTED] wrote:
Hi.
How can I sum a row and show the sum for each row???
For example, in a finances table that have the total movimentation(debit/credit)
in the bank.
i.e:
CREATE TABLE TB1 (id integer primary key, value numeric);
insert into tb1 values (1,20);
insert into tb1 values (2,2);
insert into tb1 values (3,3);
insert into tb1 values (4,17);
insert into tb1 values (5,-0.5);
insert into tb1 values (6,3);
I want a query that returns:
-id- | --- value --- | --- subtot ---
1 | 20.00 | 20.00
2 | 2.00 | 22.00
3 | 3.00 | 25.00
4 | 17.00 | 42.00
5 | -0.50 | 41.50
6 | 3.00 | 44.50
The subtot colum will be the "prev. subtot colum"+"value colum". :-/
I dont know how to make the "subtot" colum, I tried to use the sum() function
but it not works correctly.
Any idea???
Thanks.
---------------------------(end of broadcast)---------------------------
TIP 5: Have you checked our extensive FAQ?
http://www.postgresql.org/docs/faq
CREATE TABLE tb1 (id integer primary key, value numeric);
CREATE TYPE subtotal_type AS (id integer, value numeric, subtotal numeric);
CREATE OR REPLACE FUNCTION subtotal () RETURNS SETOF subtotal_type AS $$
DECLARE
tbrow RECORD;
sbrow subtotal_type;
BEGIN
sbrow.subtotal := 0;
FOR tbrow IN
SELECT id, value FROM tb1 ORDER BY id
LOOP
sbrow.id := tbrow.id;
sbrow.value := tbrow.value;
sbrow.subtotal := sbrow.subtotal + tbrow.value;
RETURN NEXT sbrow;
END LOOP;
RETURN;
END;
$$ LANGUAGE plpgsql;
insert into tb1 (id, value) values (1, 20.0);
insert into tb1 (id, value) values (2, 2.0);
insert into tb1 (id, value) values (3, 3.0);
select * from subtotal();
---------------------------(end of broadcast)---------------------------
TIP 5: Have you checked our extensive FAQ?
http://www.postgresql.org/docs/faq
