Hi Oliveiros,
yes, the date is always incremented - but anyway the date column is not really
the point!
Actually the first tow columns are relevant.
I want them gouped together as indicated, adding up column 1 in the blocks with
identical second column, but not adding up over all the rows.
Hope I could express it!
Mit freundlichen Grüßen / Best Regards
Rainer Stengele
__|___
| Dipl. Inf. (Univ.) Rainer Stengele
| Technical Control - System Administration
|
| email : [email protected]
| voice/fax: ++49-9131-7778-85/88
| WWW : http://www.diplan.de
|
| diplan GmbH
| Wetterkreuz 27
| 91058 Erlangen, Germany
Diese E-Mail kann vertrauliche und/oder rechtlich geschützte Informationen
enthalten. Wenn Sie nicht der richtige Adressat sind oder diese E-Mail
irrtümlich erhalten haben, informieren Sie bitte den Absender und vernichten
Sie diese Mail. Das unerlaubte Kopieren sowie die unbefugte Weitergabe dieser
Mail ist nicht gestattet.
This e-mail may contain confidential and/or privileged information. If you are
not the intended recipient (or have received this e-mail in error) please
notify the sender immediately and destroy this e-mail. Any unauthorized
copying, disclosure or distribution of the material in this e-mail is strictly
forbidden.
Am 22.07.2010 15:18, schrieb Oliveiros d'Azevedo Cristina:
> Howdy, Rainer.
>
> Please advice me,
>
> The dates always follow that sequential pattern?
>
> Or can be holes on the dates sequence?
>
> Best,
> Oliveiros
>
> ----- Original Message ----- From: "Rainer Stengele"
> <[email protected]>
> To: <[email protected]>
> Sent: Thursday, July 22, 2010 9:09 AM
> Subject: [SQL] grouping subsets
>
>
>> Hi,
>>
>> having a table similar to
>>
>> | 1 | B | [2010-07-15 Do] |
>> | 1 | B | [2010-07-16 Fr] |
>> |---+---+-----------------|
>> | 2 | C | [2010-07-17 Sa] |
>> | 2 | C | [2010-07-18 So] |
>> |---+---+-----------------|
>> | 1 | B | [2010-07-19 Mo] |
>> | 1 | B | [2010-07-20 Di] |
>> | 1 | B | [2010-07-21 Mi] |
>> | 1 | B | [2010-07-22 Do] |
>> |---+---+-----------------|
>> | 3 | D | [2010-07-23 Fr] |
>>
>> a simple group by gives me:
>>
>> | 6 | B |
>> | 4 | C |
>> | 3 | D |
>>
>>
>> What I want to get is the values grouped by "subset", where a subset is a
>> set of rows with identical column until the colum changes.
>> Is there a way to get
>>
>> | 2 | B |
>> | 4 | C |
>> | 4 | B |
>> | 3 | D |
>>
>> by SQL only?
>>
>> - Rainer
>>
>>
>>
>>
>>
>> --
>> Sent via pgsql-sql mailing list ([email protected])
>> To make changes to your subscription:
>> http://www.postgresql.org/mailpref/pgsql-sql
>
>
--
Sent via pgsql-sql mailing list ([email protected])
To make changes to your subscription:
http://www.postgresql.org/mailpref/pgsql-sql