Howdy, Rainer.
It's been a while, so I don't know if you are still interested in this
problem or if you, in the meantime, found yourself a solution,
but I've tried this on a local copy of the example you provided and it
seems to work.
The problem is that I suspect that if you have several thousands of records
on your table it will become slow...
Best,
Oliveiros
SELECT SUM(tudo.parcela),tudo.a
FROM
(
SELECT fo.parcela,fo.a,fo.b,fo.c,MIN(th.c) as d
FROM
(
SELECT se.a as parcela,se.b as a,se.c as b, MAX(pr.c) as c
FROM
yourTable se
LEFT JOIN
(
SELECT a.*
FROM yourTable a
JOIN yourTable b
ON (b.b <> a.b)
AND ((age(a.c,b.c) = '1 day'::interval)
)
) pr
ON pr.b = se.b
AND se.c >= pr.c
GROUP BY se.a,se.b,se.c
) fo
LEFT JOIN
(
SELECT a.*
FROM yourTable a
JOIN yourTable b
ON (b.b <> a.b)
AND ((age(a.c,b.c) = '-1 day'::interval)
)
) th
ON fo.a = th.b
AND fo.b <= th.c
GROUP BY fo.parcela,fo.a,fo.b,fo.c
) tudo
GROUP BY tudo.a,tudo.c,tudo.d
To: <pgsql-sql@postgresql.org>
Sent: Thursday, July 22, 2010 9:09 AM
Subject: [SQL] grouping subsets
Hi,
having a table similar to
| 1 | B | [2010-07-15 Do] |
| 1 | B | [2010-07-16 Fr] |
|---+---+-----------------|
| 2 | C | [2010-07-17 Sa] |
| 2 | C | [2010-07-18 So] |
|---+---+-----------------|
| 1 | B | [2010-07-19 Mo] |
| 1 | B | [2010-07-20 Di] |
| 1 | B | [2010-07-21 Mi] |
| 1 | B | [2010-07-22 Do] |
|---+---+-----------------|
| 3 | D | [2010-07-23 Fr] |
a simple group by gives me:
| 6 | B |
| 4 | C |
| 3 | D |
What I want to get is the values grouped by "subset", where a subset is a
set of rows with identical column until the colum changes.
Is there a way to get
| 2 | B |
| 4 | C |
| 4 | B |
| 3 | D |
by SQL only?
- Rainer
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