ID: 29686
Comment by: jakub dot phpbug at horky dot net
Reported By: swalk at prp dot physik dot tu-darmstadt dot de
Status: Open
Bug Type: Arrays related
Operating System: Linux
PHP Version: 5CVS-2004-08-15 (dev)
New Comment:
I'm afraid that is caused just by the line
$a = "foo";
which re-sets the $a variable to string, so it is no longer an array
and can't be enumerated by next loop...
Previous Comments:
------------------------------------------------------------------------
[2004-08-15 12:37:33] swalk at prp dot physik dot tu-darmstadt dot de
Description:
------------
When using foreach with an array that has been referenced before, it
behaves oddly if you re-set the variable inside the loop - it loses the
array it originally worked on. That doesn't happen if you leave the line
creating the reference out.
Reproduce code:
---------------
<?php
$a = array(1,2,3);
$b =& $a; // this line causes the bug
// $a =& $a; does it too
foreach($a as $v) {
print "$v\n";
$a = "foo";
}
Expected result:
----------------
1
2
3
Actual result:
--------------
1
Warning: Invalid argument supplied for foreach() in /home/et/test.php
on line 4
------------------------------------------------------------------------
--
Edit this bug report at http://bugs.php.net/?id=29686&edit=1
