Addressed to: "JJeffman" <[EMAIL PROTECTED]>
"PHPDB" <[EMAIL PROTECTED]>
"bill" <[EMAIL PROTECTED]>
** Reply to note from "JJeffman" <[EMAIL PROTECTED]> Sat, 17 Feb 2001 13:11:20
-0300
>
> Try this way :
>
> "select t1.memberID,t1.choice,t2.memberID, t2.choice from table as t1, table
> as t2 where t1.choice = 2 and t2.choice =3"
>
> It works, but you'll going to have as many records as the bigger number of
> records between choice=2 and choice = 3, no matter you use the distinct
> keyword or not. I
> think you can give your problem another approach, splitting it in two
> queries and joining the result sets through php script.
>
> Sometimes you can't put SQL to do all the work.
Not all that often though... :)
SELECT t1.memberID
FROM Table AS t1, Table AS t2
WHERE t1.MemberID = t2.MemberID
AND t1.Choice = 2
AND t2.Choice = 3;
Unless you have more than one entry for a member of choice 2 or choice 3
this will give you a list of memberIDs which have both choice 2 and
choice 3 records. If you find you have duplicate memberIDs, you can add
a DISTINCT clause to the select.
> > I have a table with three simple columns: id(unique), memberID, and
> > choice
> >
> >
> > I want to find out which memberIDs have BOTH choice 2 AND choice 3.
Rick Widmer
Internet Marketing Specialists
http://www.developersdesk.com
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