yep, that's basically what i use for this sort of thing - it's a nice short
simple function, and works a treat. Obviously if you'd rather be passing the
actual colour name to the next step, you use printf("<option
value=%s>%s</option>", $myrow["colorname"], $myrow["colorname"]);
I also prefer to use printf("<option value=\"%s\"> so it has the value in
quotes - just a fussy html thing i do though.

-----Original Message-----
From: Matthew Crouch [mailto:[EMAIL PROTECTED]]
Sent: 13 December 2001 22:58
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Re: Dynamically populating a dropdown box


I'm no expert, and my code is probably buggy, but I think this is the gist
of it:

<select name="color">
<?
$result = mysql_query("SELECT * from colors");
while ($myrow = mysql_fetch_array($result)) {
printf("<option value=%s>%s</option>", $myrow["colorid"],
$myrow["colorname"]);
}
?>
</select>


Chris Payne wrote:

> Hi there everyone,
>
> I have a shopping cart which is starting to work nicely, but I have to
select size/color from the entries, how do I do this dynamically in PHP with
MySQL?  I need them to be dropdown form boxes but haven't got a clue how to
populate them from the fields of my database.
>
> Please help me with example code if possible, it would be greatly
appreciated :-)
>
> Thank you everyone
>
> Regards
>
> Chris


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