I don't know for sure if this works, but you may try simply adding a line with the name of the variable in the PHP code.
For example, this works - I don't know, however, if it works with multiple lines: <? $lala="echo"; $lala "It works!"; // echoes "It works!" ?> HTH Bogdan Keith Posehn wrote: > Quick question for you guru's out there: > > I have a set of dynamic pages. In the mysql database, I have most of my > content stored and retrieve it with queries sent from php. Is there a way to > have php send the query, get the data which _includes_ php code in it, and > then process the code from the query as if it were a normal php code, before > going on? -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
